Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
- Your returned answers (both index1 and index2) are not zero-based.
- You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9 Output: [1,2] Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
SOLVE
class Solution {
public int[] twoSum(int[] numbers, int target) {
int[] result = new int[2];
if(numbers == null || numbers.length == 0)
return result;
int start = 0;
int end = numbers.length-1;
while(start < end)
{
if(numbers[start] + numbers[end] == target){
result[0] = start + 1;
result[1] = end + 1;
return result;
}
else if(numbers[start] + numbers[end] > target){
end--;
}
else start++;
}
return result;
}
}
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